FORCE AND ACCELERATION: Net Force Exerted on a Ring

Q: How may we determine the net force ( F ) exerted on the ring below? A: We must first reduce the F1 and F2 vectors into their x/y-components: The F1y and F2y components of F1 and F2 oppose the motion of F3. The net force in the y-direction is as follows: Fnety = F2yContinue reading “FORCE AND ACCELERATION: Net Force Exerted on a Ring”