INTRODUCTION TO ELECTRONICS: The Superposition Theorem

Most of the circuits we’ve encountered thus far contain a single voltage ( V ) source that provides current ( I ) to the system. Suppose, however, that a current determination must be made for the following dual-voltage circuit type: The presence of two voltage sources eliminates any series-parallel relationships that would exist between theContinue reading INTRODUCTION TO ELECTRONICS: The Superposition Theorem

INTRODUCTION TO ELECTRONICS: A Conceptual Analysis of Thevenin’s Theorem

A physical system would be meaningless without an observer. Conclusions about electrical systems are oftentimes made from the vantage point of the source ( Vs ), but this need not be the case. If a portion of a circuit is “ opened “, an observer can view the source and other components from the newlyContinue reading INTRODUCTION TO ELECTRONICS: A Conceptual Analysis of Thevenin’s Theorem

INTRODUCTION TO ELECTRONICS: Voltage Dividers With Resistive Loads ( Part 1 )

A series circuit that contains two equal-value resistors ( R ) will split the amount of work ( J ) done by the charges equally: Prior to arrival at R1, a coulomb of charged particles ( I ) will contain 10.0 J of energy available to perform work. After passing through R1, the charges willContinue reading INTRODUCTION TO ELECTRONICS: Voltage Dividers With Resistive Loads ( Part 1 )

INTRODUCTION TO ELECTRONICS: Voltage Divider Principle in Series-Parallel Circuits

The voltage-divider formula is expressed as follows: Vx = ( Rx / RT )( Vs ) This formula is used to determine how series resistors ( R ) split voltage drops apart as current passes through them. The net voltage drop across a series circuit’s resistors is always ( ignoring small losses ) equal toContinue reading INTRODUCTION TO ELECTRONICS: Voltage Divider Principle in Series-Parallel Circuits

INTRODUCTION TO ELECTRONICS: Parallel Circuits

In the study of parallel resistor ( Rx ) circuits, where “ x “ is the number of a particular resistor ( x = 1, 2, 3, … n ), a common point of confusion regards how the total resistance ( Rt ) of the circuit is always less than the lowest calculated resistor value.Continue reading INTRODUCTION TO ELECTRONICS: Parallel Circuits

INTRODUCTION TO ELECTRONICS: Parallel Circuits

We have previously seen how all of the current ( I ) within a series circuit will pass through each resistor ( R ) situated within it. The sum of the energy drops that a coulomb ( C ) of charge loses as it traverses a circuit is equal to the voltage ( V )Continue reading INTRODUCTION TO ELECTRONICS: Parallel Circuits

INTRODUCTION TO ELECTRONICS: Kirchhoff’s Laws ( Part 3 )

Thus far, we have used a single-loop series circuit to demonstrate the principles of Kirchhoff’s Loop Rule. What if, however, a circuit has multiple loops through which current ( I ) travels? To further complicate things, what if each loop contains a voltage ( V ) source? How will it be possible to determine theContinue reading “INTRODUCTION TO ELECTRONICS: Kirchhoff’s Laws ( Part 3 )”

ELECTRONICS: Kirchhoff’s Laws

Q: What are the values of the currents ( I ) and unknown voltage drops ( V ) across the resistors ( R ) pictured below? A: The first problem-solving step involves assigning labels to the junctions ( j ) in the circuit: We must now sketch the currents flowing in the circuit: The currentContinue reading “ELECTRONICS: Kirchhoff’s Laws”

ELECTRICITY: Wattage

Q: A parallel electrical circuit connects the electrical outlets located within a room. A 20-A fuse is put into place to protect the circuit from unexpected surges of current ( I ). The voltage drop across each circuit element is V = 120 V. What is the maximum power ( W ) output that canContinue reading “ELECTRICITY: Wattage”

FINDING THE LOWEST COMMON DENOMINATOR ( LCD ) OF FRACTIONS AND DETERMINING THE TOTAL RESISTANCE ( Rt ) OF PARALLEL ELECTRICAL CIRCUITS:

FINDING THE LOWEST COMMON DENOMINATOR: Let’s first envision putting two half pieces of a pie together to get a full pie. Numerically, this would involve adding ( 1/2 ) + ( 1/2 ) = ( [ 1 + 1 ] / 2 ) = ( 2/2 ) = 1 whole pie. This example was madeContinue reading “FINDING THE LOWEST COMMON DENOMINATOR ( LCD ) OF FRACTIONS AND DETERMINING THE TOTAL RESISTANCE ( Rt ) OF PARALLEL ELECTRICAL CIRCUITS:”