Tag Archives: Voltage divider formula

INTRODUCTION TO ELECTRONICS: Voltage Dividers With Resistive Loads ( Part 1 )

A series circuit that contains two equal-value resistors ( R ) will split the amount of work ( J ) done by the charges equally: Prior to arrival at R1, a coulomb of charged particles ( I ) will contain 10.0 J of energy available to perform work. After passing through R1, the charges willContinue reading “INTRODUCTION TO ELECTRONICS: Voltage Dividers With Resistive Loads ( Part 1 )“

INTRODUCTION TO ELECTRONICS: Voltage Divider Principle in Series-Parallel Circuits

The voltage-divider formula is expressed as follows: Vx = ( Rx / RT )( Vs ) This formula is used to determine how series resistors ( R ) split voltage drops apart as current passes through them. The net voltage drop across a series circuit’s resistors is always ( ignoring small losses ) equal toContinue reading “INTRODUCTION TO ELECTRONICS: Voltage Divider Principle in Series-Parallel Circuits“

INTRODUCTION TO ELECTRONICS: The Voltage-Divider Formula

Thus far, we have seen how the sum of voltage drops across a series circuit is equal to the voltage value of the source ( Vs ):  Vs = V1 + V2 + V3 In the aforementioned scenario, three resistors are situated within a non-diverging electrical path; thus, each resistor along the electrical path hasContinue reading “INTRODUCTION TO ELECTRONICS: The Voltage-Divider Formula“

INTRODUCTION TO ELECTRONICS: Series Circuits

A series circuit is one in which electric current ( I ) travels along a closed path that does not split apart: *** Note: Conventional current consists of positive charges that flow from the positively charged anode to the negatively charged cathode. In reality, negatively charged electrons flow in the opposite direction. *** The diagram,Continue reading “INTRODUCTION TO ELECTRONICS: Series Circuits”